DISCUSSION FORUM


USER QUERY
VISHAL RAJPUT
2019-12-05
pH=pka+ log[bicarbonate/carbonic acid]

7.4= 6.1 + log [bicarbonate/carbonic acid]

1.3 = log [bicarbonate/carbonic acid]
antilog[1.3] = bicarbonate/carbonic acid
10 x 2 = bicarbonate/carbonic acid

20/1 = bicarbonate/carbonic acid
SHREYA SHARMA
2019-12-03
The pH of blood of a healthy person is maintained at 7.40+- 0.05, assuming that this pH is maintained entirely by the bicarbonate buffer (pka1 and pka2 of carbonic acid are 6.1 and 10.3 respectively), the molar ratio of [bicarbonate]/[carbonic acid] in the blood is?
Please explain how to solve this numerical?